July 22, 201214 yr Author I'm bunting him 100 times out of 100 in that situation. Why? There was a HUGE hole on the right side of the infield.
July 22, 201214 yr I fully believe that Morgan and I both have the same throwing motion with our left hands.
July 22, 201214 yr Why? There was a HUGE hole on the right side of the infield. Because at that point you're playing for one run. If they shift to pull side they are most likely pitching him in, or trying to. Makes going the other way much more difficult.
July 22, 201214 yr Realistically, you don't have much better of a chance getting the runner home from third with one out than you do getting the runner in from second with zero outs. Please explain.
July 22, 201214 yr Please explain. Baseball Between the Numbers: Why Everything You Know About the Game Is Wrong - Jonah Keri - Google Books You only increase your odds of scoring by 3.6% by changing the situation. That obviously is less because there is a chance of an unsuccessful sac bunt.
July 22, 201214 yr Baseball Between the Numbers: Why Everything You Know About the Game Is Wrong - Jonah Keri - Google Books You only increase your odds of scoring by 3.6% by changing the situation. That obviously is less because there is a chance of an unsuccessful sac bunt. But more of a chance of not getting the runner to 3rd when not bunting. If you don't move that runner to 3rd the chance to score goes from 66.1% to 41.4%. I'll take my chances with a runner on 3rd and 1 out all day, especially if I'm getting there by bunting my 8 hitter.
Archived
This topic is now archived and is closed to further replies.