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BRAINTEASER: My Three Sons

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Here's one that has brought about a lot of discussion from students and puzzle fans alike over the years. I have had many people question me about this one. Even after I espouse my credentials of teaching probability and statistics for twenty years, some still question this one. It is really not a particularly difficult puzzle, but it is one that ,once you have the answer, it may not "feel" quite right. Some of you will probably get it right away; some will say I am wrong. Here goes:

 

 

*******************************************************

Mrs. Mathemagician has three children, at least one of which , is a boy. What is the probability that she has three sons?

 

 

*******************************************************

I was torn between 1 in 3 and 1 in 4. It looks like there are 3 possible choices, 2 boys and a girl, 1 boy and 2 girls, and 3 girls, but they don't have equal chances of occuring. But in reality there are 4 possiblities: BBB, BGG, BBG and BGB. So the odds of having two boys and one girl are 50/50 and the odds of having all boys or two girls are each 1 in 4.

  • Author

I'll make it multi-choice. Pick a letter:

 

(a) 1/3

 

(b) 1/4

 

© 1/6

 

(d) 1/7

 

(e) 1/8

(b)

 

And you all better not peek at my answers.

We are assuming that each pregnancy has a 50/50 chance, which we are finding out is not necessarily true. Some couples are more prone to having children on the same sex....ask my neighbor with 5 girls.

 

If we are talking strictly math here, I would say, there are three possible scenarios.

 

One boy and 2 girls

 

Two boys and 1 girl

 

Three boys

 

So I would say 1 in 3.

(d) 1/7

 

There are 8 potential combos when having three kids:

 

BBB BBG BGB BGG

GGG GGB GBG GBB

 

Since it said "...at least one is a boy", that rules out the GGG, leaving 7 different choices. (Remember, it does not say that the first child is a boy.) Only one of the choices is all three boys.

 

Hence, one in seven chance.

I know a lady that had 9 children, all of which were boys. You have a 50/50 shot at having a boy everytime.

My guess is 1 in 3. You know one is a boy so no reason to factor him in. The remaining 2 childern can either be BB, BG, GG.

 

So my answer is A.

I'll make it multi-choice. Pick a letter:

 

(a) 1/3

 

(b) 1/4

 

© 1/6

 

(d) 1/7

 

(e) 1/8

 

 

(D) 1/7

So far we have 2 a's, 1 b, and two d's.

e. .5 X .5 X .5 = .125

1/4

 

(1/2 times 1/2; since one is already a boy - if that hadn't already been stated, the answer would be 1/8).

My guess is 1 in 3. You know one is a boy so no reason to factor him in. The remaining 2 childern can either be BB, BG, GG.

 

So my answer is A.

 

That answer would be correct, except you left out the fourth possibility - GB.

A variation of this question used to come up in elementary statistics class. Mrs. A has three boys. What is the probability that her next child will be a boy?

 

Of course, the answer is 1/2, but there were an AWFUL lot of folks who read more into it than necessary.

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