April 1, 200818 yr Author Here is a graph to help visualize it. (Hope I did this right ) The blue line passes through the points (1,1), (2,2), (3,3) etc. This means that every point below the blue line represents where x > y. Amd every point above the blue line represents where x I plotted the triangle using the 3 points of this problem. The yellow area is where x y. . The graph is perfectly drawn. The ratio of the area of the small triangle to the area of the big triangle will reveal the answer.
April 1, 200818 yr Here is a graph to help visualize it. (Hope I did this right ) The blue line passes through the points (1,1), (2,2), (3,3) etc. This means that every point below the blue line represents where x > y. Amd every point above the blue line represents where x I plotted the triangle using the 3 points of this problem. The yellow area is where x y. . I had worked it out this way initially, then got off track somehow.
April 1, 200818 yr I made a math error in my earlier guess. So now I have to change my answer to 1 in 10
April 2, 200818 yr Author I made a math error in my earlier guess. So now I have to change my answer to 1 in 10 BINGO!!!
April 2, 200818 yr I'd guess about 25 years ago. :lol: Actually, there may be some argument as to who failed whom. :sssh:
April 2, 200818 yr I used the formula; a = .5(bh) to find the area of the triangles, where a=area b=base h=height The area of the big triangle = 3. The base was 2 and height was 3, so area = .5(2x3) = .5(6) = 3. The are of the small triangle = .3. The base was 1 and height was .6, so area = .5(1x.6) = .5(.6) = .3 If the area of the small triangle was .3 and the area of the big triangle was 3, then the probability of randomly plotting a point in the small triangle (where x > y) was 1 in 10 or 10%.
April 2, 200818 yr I'd try to explain how I came up with my answer; but there's a good chance I'd blow a fuse in my head somewhere. :creepy:
April 2, 200818 yr Author I used the formula; a = .5(bh) to find the area of the triangles, where a=area b=base h=height The area of the big triangle = 3. The base was 2 and height was 3, so area = .5(2x3) = .5(6) = 3. The are of the small triangle = .3. The base was 1 and height was .6, so area = .5(1x.6) = .5(.6) = .3 If the area of the small triangle was .3 and the area of the big triangle was 3, then the probability of randomly plotting a point in the small triangle (where x > y) was 1 in 10 or 10%. beautifully done.
April 2, 200818 yr I used the formula; a = .5(bh) to find the area of the triangles, where a=area b=base h=height The area of the big triangle = 3. The base was 2 and height was 3, so area = .5(2x3) = .5(6) = 3. The are of the small triangle = .3. The base was 1 and height was .6, so area = .5(1x.6) = .5(.6) = .3 If the area of the small triangle was .3 and the area of the big triangle was 3, then the probability of randomly plotting a point in the small triangle (where x > y) was 1 in 10 or 10%. Nice:ylsuper:
Archived
This topic is now archived and is closed to further replies.