Final

This result should tell everyone that whoever the #4 seed in the district winds up being won't roll over for anyone. Takes Creek, who'll host the district, only losing to Dunbar by 10 tonight should say the same thing about them in the 4/5 game and possibly beyond. That district is going to be really intense.

 

Someone correct me if I'm wrong, but as things stand right now, the seeding is like this:

 

1. Lexington Catholic (5-2):

Remaining Games: vs. LCA on 2/12;

#1 seed with win over LCA;

Flip for #1 w/ LCA if LCA beats Catholic & Creek.

 

2. Lexington Christian (4-2):

Remaining games: vs. Tates Creek on 2/10, vs. Lexington Catholic on 2/12

Lose both, then a flip for 2/3 with LAF based on LCA's 2 head-to-head wins over Dunbar;

Win one of the two, then guaranteed to be the #2 seed at lowest.

Beat both & then tied with Catholic for the #1 seed & coin flip.

 

3/4. Lafayette (4-4):

LAF/PLD split H2H; Coin Flip for 3rd/4th at least

LAF won by 14, PLD by 4 if this is the tiebreaker

 

3/4. Dunbar (4-4):

LAF/PLD split H2H; Coin Flip for 3rd/4th at least

LAF won by 14, PLD by 4 if this is the tiebreaker

Dunbar was swept by LCA & cannot finish ahead of them

 

5. Tates Creek (1-6):

5 seed regardless of future outcomes

Remaining Game vs. LCA on 2/10

 

 

What all of the above means:

 

If LCA beats Lexington Catholic & Tates Creek, then there's a flip for #1 & #2 and a flip for #3 & #4.

 

If LCA beats Tates Creek & loses to Catholic, then they are the #2 and Dunbar/Lafayette flip for #3 & #4.

 

If LCA loses both, then they flip with Lafayette for the #2 and #3. I'm guessing that if Lafayette loses that flip, they then flip with Dunbar for the #4.

 

 

All that make sense to everyone? :eek:

Edited February 7, 201511 yr by JokersWild24

If I'm right this means that Catholic is guaranteed a 1st round bye regardless of the outcome of their game with LCA. HUGE for them

 

Someone correct me if I'm wrong, but as things stand right now, the seeding is like this:

 

2. Lexington Christian (4-2):

Remaining games: vs. Tates Creek on 2/10, vs. Lexington Catholic on 2/12

Lose both, then a flip for 2/3 with LAF based on LCA's 2 head-to-head wins over Dunbar;

Win one of the two, then guaranteed to be the #2 seed.

Win both, then tied with Catholic for the #1 seed & coin flip

 

If LCA beats Lexington Catholic & Tates Creek, then there's a flip for #1 & #2 and a flip for #3 & #4.

 

If LCA loses both, then they flip with Lafayette for the #2 and #3. I'm guessing that if Lafayette loses that flip, they then flip with Dunbar for the #4.

 

 

All that make sense to everyone? :eek:

 

Yes it makes sense. But it’s wrong in stated outcomes for LCA.

 

If LCA wins both their remaining games, they will finish 6-2, meaning Catholic will be 5-3, and LCA will be outright winner, no tiebreaker involved. Tiebreaker for 3&4 with Lafayette and Dunbar.

 

If LCA beats Catholic but only after a loss to Creek, both are 5-3 and you are correct that there is a tiebreaker for 1&2, and another for 3&4.

 

If LCA loses to Catholic, Catholic is 6-2, and is the outright winner, as you noted. In that case LCA can be 5-3 or 4-4 based on their Tates Creek outcome, and you are correct in the options but the implementation is arguable at 4-4.

 

A 5-3 LCA gets sole 2nd place, and Lafayette and Dunbar follow the 2-way tiebreaker mechanisms.

 

If LCA is 4-4, the 3-way tiebreaker mechanisms will be used instead. The three-way tie breaker description is not clearly articulated relative to its Boolean algebraic evaluation possibilities, and lively discussion will ensue before the schools come to an honorable and well-reasoned decision. It is perhaps better to just wait and see if LCA beats Creek before worrying about this possibility.

If I'm right this means that Catholic is guaranteed a 1st round bye regardless of the outcome of their game with LCA. HUGE for them

 

1,2, and 3 seeds go on lines in a bracket of 4. The 4th line goes to the winner of a game between 4&5 seeds. Call that a first round or a play-in game, but 1,2, &3 seeds only have to win their first game to qualify for the regional, and you'll be a 1 or 2 my friend. Enjoy.

Whoops. Good catch Casual Fan.

Fixed the above post, and thanks again for the catch. I'm now really wondering what the three way tie breaker is.

Fixed the above post, and thanks again for the catch. I'm now really wondering what the three way tie breaker is.

 

1st...Head to head among all 3 teams involved.

2nd...Random draw among the three teams.

 

http://khsaa.org/httpdocs/basketball/districtregion/districtseedingplans/District%2043.pdf

1st...Head to head among all 3 teams involved.

2nd...Random draw among the three teams.

 

http://khsaa.org/httpdocs/basketball/districtregion/districtseedingplans/District%2043.pdf

 

 

So how would it work when 3 teams are tied for the same record but of those, 1 won the head to head against the other twice, and then the other two all had identical head-to-head records versus one another?

1st...Head to head among all 3 teams involved.

2nd...Random draw among the three teams.

 

http://khsaa.org/httpdocs/basketball/districtregion/districtseedingplans/District%2043.pdf

 

The three-way tiebreaker will only come into play if LCA were to lose both of their last two games and finish 4-4 in the district. In that event, LCA would still be the #2 seed in the district tourney, with Lafayette #3 and Dunbar #4. The reason why is that in head-to-head games played among the three teams tied, the records would be:

 

LCA 3-1 (wins over Lafayette and Dunbar twice; loss to Lafayette)

Lafayette 2-2 (wins over LCA and Dunbar; losses to LCA and Dunbar)

Dunbar 1-3 (win over Lafayette; losses to Lafayette and LCA twice)

 

So, regardless of the outcome of the remaining games, LCA cannot be worse than a #2 seed in the 43rd district tournament, and Lafayette and Dunbar cannot be better than a #3 seed.

 

The 43rd is going to end up with LexCath and LCA as the top two seeds (the order still to be determined by remaining games) with Lafayette and Dunbar in a coin flip for the #3 and #4 spots (unless LCA loses both remaining games, then Lafayette gets the #3 seed automatically based on its better head-to-head record than Dunbar).

The three-way tiebreaker will only come into play if LCA were to lose both of their last two games and finish 4-4 in the district. In that event, LCA would still be the #2 seed in the district tourney, with Lafayette #3 and Dunbar #4. The reason why is that in head-to-head games played among the three teams tied, the records would be:

 

LCA 3-1 (wins over Lafayette and Dunbar twice; loss to Lafayette)

Lafayette 2-2 (wins over LCA and Dunbar; losses to LCA and Dunbar)

Dunbar 1-3 (win over Lafayette; losses to Lafayette and LCA twice)

 

So, regardless of the outcome of the remaining games, LCA cannot be worse than a #2 seed in the 43rd district tournament, and Lafayette and Dunbar cannot be better than a #3 seed.

 

The 43rd is going to end up with LexCath and LCA as the top two seeds (the order still to be determined by remaining games) with Lafayette and Dunbar in a coin flip for the #3 and #4 spots (unless LCA loses both remaining games, then Lafayette gets the #3 seed automatically based on its better head-to-head record than Dunbar).

 

The bolded is off.

That's a tough district. Any of the top 4 could win it. I don't know much about Tate's Creek just going by there record in the district.

The bolded is off.

 

Sorry, misread that and see what you were saying it.

 

LCA won over Lafayette once and Dunbar twice, then lost to Lafayette once.

 

I read it as wins over (both) LCA and Dunbar twice.

 

Still, I thought that if LCA and Lafayette split, then they'd flip for the 2/3 and if Lafayette then was the 3, then they'd flip with Dunbar for the 3/4.

 

Am I mistaken there?

Sorry, misread that and see what you were saying it.

 

LCA won over Lafayette once and Dunbar twice, then lost to Lafayette once.

 

I read it as wins over (both) LCA and Dunbar twice.

 

Still, I thought that if LCA and Lafayette split, then they'd flip for the 2/3 and if Lafayette then was the 3, then they'd flip with Dunbar for the 3/4.

 

Am I mistaken there?

 

In this hypothetical, there would be three teams tied at 4-4. In the District Tournament Seeding Plan there is no mention whatsoever of a "coin flip" in the three-way tie-breaking mechanism.

In this hypothetical, there would be three teams tied at 4-4. In the District Tournament Seeding Plan there is no mention whatsoever of a "coin flip" in the three-way tie-breaking mechanism.

 

Sorry, just quoting the language that was used in the past. The plan mentions a coin flip in the two way and a draw in the 3 way. Regardless, coin flip/draw, same difference. The seed is left to chance and it's equal odds/probability between who gets what.

 

What I'm asking is whether or not the fact that LCA, Dunbar, and Lafayette could all be tied would mean that there could be a flip between LCA and Lafayette for the 2/3, and then when happens if Lafayette winds up being the one who get the #3 in that one.

 

Is it nothing because Lafayette was also tied with a team that had the tie breaker over Dunbar in head-to-head wins, so Dunbar is the #4?

 

Or is it that Lafayette now is in a two way tie with Dunbar for the #3/#4 spots because Lafayette and Dunbar would then have to flip, which is what you do for another 2 way tiebreaker?